water trampolines image
Marsha Mas
A 10-ft wide round water trampoline is floating in a pool measuring x ft by x ft. Find a polynomial for the remaining surface area of the pool
Answer
Supposing x to be greater than or equal to 10:
Area of the pool: x^2 sq. feet
Area of the trampoline: (Ï (10/2)^2) = 25Ï sq. feet
So the remaining area = x^2 - 25Ï sq. feet
(If x is less than 10, the remaining area can be calculated, but it becomes complicated because of the overlap of the trampoline on the surrounding land. The word "floating" suggests that x is not less than 10.)
Supposing x to be greater than or equal to 10:
Area of the pool: x^2 sq. feet
Area of the trampoline: (Ï (10/2)^2) = 25Ï sq. feet
So the remaining area = x^2 - 25Ï sq. feet
(If x is less than 10, the remaining area can be calculated, but it becomes complicated because of the overlap of the trampoline on the surrounding land. The word "floating" suggests that x is not less than 10.)
A 10-ft wide round water trampoline is floating in a pool measuring x ft by x ft. Find a polynomial for the re?
Mangie Bam
A 10-ft wide round water trampoline is floating in a pool measuring x ft by x ft. Find a polynomial for the remaining surface area of the pool
Answer
r=5
xsquared-25pi would be the area not covered
r=5
xsquared-25pi would be the area not covered
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